NIFT UG 2018 Question Paper with solutions

Question : 6 of 150

Marks: +1, -0

The least number, which is to be added to the greatest number of 4 digits so that the sum may be divisible by

345,

Solution:

The largest 4 digit number

=9999

345) 9999 (28
690
3099
2760
339

∴

Required number to be added

=345-339=6

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