NIFT UG 2011 Question Paper with solutions

Question : 29 of 150

Marks: +1, -0

Find the least number which when divided by 36, 48 and 64 leaves the remainders 25,37 and 53 respectively.

Solution:

Here,

36–25=11

48–37=11

64–53=11

Required number= (L.C.M of 36, 48, 64) – 11

=576–11=565

Go to Question:

Prev Question

Next Question