NIFT PG 2009 Question Paper with solutions

Question : 146 of 150

Marks: +1, -0

A, B, C, D and E are five consecutive odd numbers. The sum of A and C is 146. What is the value of E?

Solution:

Let, five consecutive odd numbers A, B, C, D and E are,

(x+1),(x+3),(x+5),(x+7)

and

(x+9)

respectively.
Then,

A+C=146

⇒(x+1)(x+5)=146

⇒2x=140

⇒x=70

Thus, value of

E=x+9=70+9=79

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