NIACL Model Paper 9 with solutions for free online practice

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Question : 52 of 100

Marks: +1, -0

What approximate value should come in place of the question mark (?) in the following question?

4275÷ 496×(21)^2 = ?

3795
3800
3810
3875
3995

Solution:

(2)

? = 4275 ÷ 496 × 21^2

={4275×(21)^2}/496

≈

{4275 × 441}/495≈ 3800

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