NIACL Model Paper 8 with solutions for free online practice

(1) Breadth of the rectangular field = x metre
∴ Its length =$\frac{175\mathit{x}}{100}$ metre
$=\frac{7\mathit{x}}{4}$ metre
Perimeter of field

$=\left[\frac{220}{5}\right]$ metre = 44 metre
∴ $2\left[\frac{7\mathit{x}}{4}+\mathit{x}\right]=44$
⇒$\frac{7\mathit{x}+4\mathit{x}}{4}=\frac{44}{2}=22$
⇒ $11\mathit{x}=22\times 4$
⇒$\mathit{x}=\frac{22\times 4}{11}=8$ metre
∴ Length
=$\frac{7\mathit{x}}{4}=\frac{7\times 8}{4}=14$ metre
∴Required area
$=\left(14\times 8\right)$sq. metre
= 112 sq. metre