NIACL Model Paper 7 with solutions for free online practice

(5) Side of square = $\frac{32\sqrt{2}}{\sqrt{2}}$
= 32 metre
∴ Perimeter of square = $4\times 32=128$ metre
∴ Perimeter of rectangle
= 128 metre
Breadth of rectangle
= x metre (let)
∴Its length = (x + 14) metre
$\therefore 2\left(\mathit{x}+14+\mathit{x}\right)=128$
=> $2\mathit{x}+14=\frac{128}{2}=64$
⇒ $2\mathit{x}=64-14=50$
⇒$\mathit{x}=\frac{50}{2}=25$ metre
∴ Length = (25 + 14) metre
= 39 metre
∴Area of rectangle
= 39 × 25
= 975 sq. metre