NIACL Model Paper 5 with solutions for free online practice

Question : 25 of 100

Marks: +1, -0

Sum of the digits of a two digit number is 8 and the digit in the ten’s place is three times the digit in the unit’s place. What is the number?

Solution:

(d) Let ten’s digit be x and unit’s digit be 8 - x
Then, x = 3 (8 - x)
⇒

x = 24-3x,

⇒ 4x= 24
⇒

x=24/4=6

∴unit’s digit

= 8-x = 8 - 6 = 2

So, required number = 62

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