NIACL Model Paper 2 with solutions for free online practice

(b) Let present age of Yashika = x years
∴ Age of Yashika at the time of marriage
= (x - 8) years $\mathit{x}=\frac{9}{7}\left(\mathit{x}-8\right)$
⇒$7\mathit{x}=9.\mathit{x}-72\therefore \mathit{x}=\frac{72}{2}=36$ years
∴Present age of the daughter = $36\times \frac{1}{6}=6$years
∴Her daughter’s age 3 years ago = (6 - 3) = 3 years