NIACL Model Paper 2 with solutions for free online practice

Question : 13 of 100

Marks: +1, -0

How much water must be added to 100 cc of 80% solution of boric acid to reduce it to a 50% solution?

Solution:

Concentration of boric acid =80% =80 cc
Quantity of water = 20 cc
Let x cc of water be added to get the concentration of 50%.
⇒

80/{100+x}=50/100 or 80/{100+x}=1/2 or x=60 cc

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