NIACL Model Paper 10 with solutions for free online practice

(4) Let the breadth of the rectanglebe x cms
∴ Length = (x + 3) cms.
Now, 2(x + x + 3) = 50
=> 2x+ 3 = 25
=> 2x= 22
⇒ $\mathit{x}=\frac{22}{2}=11$
∴Breadth = 11cms.
and length = x + 3 = 11 +3 = 14 cms.
∴ Area of circle = Area of rectangle
⇒ $\mathit{\pi }{\mathit{r}}^2=14\times 11$
⇒ ${\mathit{r}}^2=\frac{14\times 11\times 7}{22}$
=> r = 7 cms.
∴ Diameter = 14 cms.