NIACL Model Paper 10 with solutions for free online practice

(4) Period of time between 11 a.m. and 4:30 p.m.
$=5\frac{1}{2}$ hours
Distance covered = $\left[\frac{5}{6}-\frac{3}{8}\right]$ part
$=\left[\frac{20-9}{24}\right]$ part= $\frac{11}{24}$ part
∴ Time taken in covering $\frac{11}{24}$ th part
of distance $=\frac{11}{2}$ hours
∴ Time taken in covering
$\frac{3}{8}$ th part of distance
$=\frac{11}{2}\times \frac{24}{11}\times \frac{3}{8}=\frac{9}{2}$ hours
$=4\frac{1}{2}$ hours
∴ Time when the journey was
started = 11-4:30 = 6:30 a.m.