Class 11 NEET Physics Waves Questions Questions

The given wave equation is
y=3‌sin‌

π

2

(50t−x)
y=3‌sin(25πt−

π

2

x) ....(i)
The standard wave equation is
y=A‌sin(ωt−kx) ......(ii)
Comparing(i) and (ii), we get
ω=25π,k=

π

2

Wave velocity, v=

ω

k

=

25π

(π∕2)

=50ms−1
Particle velocity, vp=

dy

dt

=

d

dt

(3‌sin(25πt−

π

2

))
=75π‌cos(25πt−

π

2

)
Maximum particle velocity, (vp)max=75πm s−1
∴

(vp)max

v

=

75π

50

=

3

2

π