When a string is divided into three segments of length l_1,l_2 and l_3 the fundamental frequencies of these three segments are \upsilon_1,\upsilon_2 and \upsilon_3 respectively. The original fundamental frequency (\upsilon) of string is (2012)

Correct Answer is : 1υ=1υ1+1υ2+1υ3

\sqrt\upsilon=\sqrt\upsilon_1+\sqrt\upsilon_2+\sqrt\upsilon_3

\upsilon=\upsilon_1+\upsilon_2+\upsilon_3

1/\upsilon=1/\upsilon_1+1/\upsilon_2+1/\upsilon_3

1/\sqrt\upsilon=1/\sqrt\upsilon_1+1/\sqrt\upsilon_2+1/\sqrt\upsilon_3

Class 11 NEET Physics Waves Questions Questions

Question : 33 of 94

Marks: +1, -0

When a string is divided into three segments of length l1,l2 and l3 the fundamental frequencies of these three segments are υ1,υ2 and υ3 respectively. The original fundamental frequency (υ) of string is

(2012)

√υ=√υ1+√υ2+√υ3
υ=υ1+υ2+υ3
1
υ
=
1
υ1
+
1
υ2
+
1
υ3
1
√υ
=
1
√υ1
+
1
√υ2
+
1
√υ3

Validate

Go to Question:

Prev Question

Next Question