Class 11 NEET Physics Thermodynamics and Kinetic Theory

Heat required to melt 1 kg ice at 0°C to water at 0°C is
Q=miceLice=(1kg)(80cal/g)
=(1000g)(80cal/g)=8×104 cal
Change in entropy, ΔS=

Q

T

=

8×104cal

(273K)

=293 cal/K
Note : In the question paper unit of latent heat of ice is
given to be cal/°C. It is wrong. The unit of latent heat of ice is cal/g.