Class 11 NEET Physics System of Particles and Rotational Motion

According to the theorem of parallel axes, the moment of inertia of the thin rod of mass M and length L about an axis passing through one of the ends is
I=ICM+Md2
Where ICM is the moment of inertia of the given rod about an axis passing through its centre of mass and perpendicular to its length and d is the distance between two parallel axes.
Here.ICM=I0,d=

L

2

∴I=I0+M(

L

2

)2=I0+

ML2

4