A uniform rod of mass 20 kg and length 5 m leans against a smooth vertical wall making an angle of 60^{\circ} with it. The other end rests on a rough horizontal floor. The friction force that the floor exerts on the rod is (Take g=10 {\m} \/ { s}^2 ) [NEET 2025]

Class 11 NEET Physics System of Particles and Rotational Motion

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A uniform rod of mass 20 kg and length 5 m leans against a smooth vertical wall making an angle of 60∘ with it. The other end rests on a rough horizontal floor. The friction force that the floor exerts on the rod is (Take g=10m∕ s2 )

[NEET 2025]

200 N
200√3N
100 N
100√3N

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