The correct relationship between the two current gains \\alpha and \\beta in a transistor is (1997)

\\alpha= \frac{\\beta}{1+\\beta}

\\alpha= \frac{1+\\beta}{\\beta}

\\beta= \frac{\\alpha}{1+\\alpha}

\\beta= \frac{\\alpha}{\\alpha-1}

Class 12 NEET Physics Semiconductor Electronics Part 1

Question : 77 of 100

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The correct relationship between the two current gains α and β in a transistor is

(1997)

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