The correct relation for \\alpha, \\beta for a transistor (2000)

Correct Answer is : β=α1−α

\\beta= \frac{1-\\alpha}{\\alpha}

\\beta= \frac{\\alpha}{1-\\alpha}

\\alpha= \frac{\\beta-1}{\\beta}

Class 12 NEET Physics Semiconductor Electronics Part 1

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The correct relation for α,β for a transistor

(2000)

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