Class 11 NEET Physics Properties of Matter Questions

Let us take the temperature of the boiling water be 100 degrees in Celsius scale and 180 degrees in Fahrenheit scale.
That is, ‌

140−32

180

=‌

C

5

‌ Therefore, ‌5×108=9C,‌‌C=60‌‌deg‌‌C
since, the temperature of boiling water is 100 deg C, the required fall is 100−60=40 degrees C.
Hence, The fall in temperature as registered by centigrade thermometer is 40 degree Celsius.