Class 11 NEET Physics Physical World, Units and Measurements

f=amxky ....(i)
Dimensions of frequency v=[M0L0T−1]
Dimensions of constant a=[M0L0T0]
Dimensions of mass m=[M]
Dimensions of spring constant k=[MT−2]
Putting these value in equation (i), we get
[M0L0T−1]=[M]x[MT−2]y
Applying principle of homogeneity of dimensions, we get
x+y=0
−2y=−1
or x=−

1

2

,y=

1

2