The potential energy of a particle moving along x-direction varies as V= {A x^2}/{\sqrt{x}+B}. The dimensions of \frac{A^2}{B} are: [NEET 2024 Re]

Correct Answer is : [M2L1∕2T−4]

[ {\M}^{3 \/ 2} {\L}^{1 \/ 2} {\T}^{-3}]

[ {\M}^2 {\L}^{1 \/ 2} {\T}^{-4}]

Class 11 NEET Physics Physical World, Units and Measurements

Section: Physics

Question : 6 of 70

Marks: +1, -0

The potential energy of a particle moving along x-direction varies as V=‌

Ax2

√x+B

. The dimensions of ‌

are:

[NEET 2024 Re]

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