Turpentine oil is flowing through a tube of length l and radius r. The pressure difference between the two ends of the tube is P . The viscosity of oil is given by \\eta= {P (r^{2}-x^{2} )}/{4 v l} where v is the velocity of oil ata distance x from the axis of the tube. The dimensions of \\eta are ( 1993 )

Correct Answer is : [ML−1T−1]

Class 11 NEET Physics Physical World, Units and Measurements

Question : 58 of 70

Marks: +1, -0

Turpentine oil is flowing through a tube of length l and radius r. The pressure difference between the two ends of the tube is P. The viscosity of oil is given by η=

P(r2−x2)

4vl

where v is the velocity of oil ata distance x from the axis of the tube. The dimensions of η are

( 1993 )

[M0L0T0]
[MLT−1]
[ML2T−2]
[ML−1T−1]

Validate

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