Class 11 NEET Physics Motion in a Straight Line Questions

Height of tap =5m. For the first drop,
5=ut+

1

2

gt2 =

1

2

×10t2=5t2 or t2=1
or t=1‌sec. It means that the third drop leaves after one second of the first drop, or each drop leaves after every 0.5 sec. Distance covered by the second drop in 0.5‌sec
=

1

2

gt2=

1

2

×10×(0.5)2 =1.25m
Therefore distance of the second drop above the ground =5−1.25=3.75m