Class 11 NEET Physics Motion in a Straight Line Questions

Distance covered by the stone in 5s is
h1=

1

2

g(5)2=

25

2

g.........(i)
Distance travelled by the stone in 10 s is
h1+h2=

1

2

g(10)2=100g....(ii)
Distance travelled by the stone in 15 s is
h1+h2+h3=

1

2

g(15)2=

225

2

g..............(iii)
Subtract (i) from (ii), we get
(h1+h2)−h1=

100

2

g−

25

2

g=

75

2

g
h2=

75

2

g=3h1...........(iv)
Subtract (ii) from (iii), we get
(h1+h2+h3)−(h2+h1)=

225

2

g−

100

g

h3=

125

2

g=5h1.......(iv)
From (i), (iv) and (v), we get h1=

h2

3

=

h3

5