Class 11 NEET Physics Laws of Motion Questions

When a stone is dropped from a height h, it hits the ground with a momentum
P=m√2gh.........(i)
Where m is the mass of the stone
When the same stone is dropped from a height 2h (i.e. 100% of initial),then its momentum with which it hits the ground becomes
P′=m√2g(2h)=√2P  (Using(i)).......(ii)
% change in momentum=

P′−P

P

×100%
=

√2P−P

P

×100%=41%