Class 12 NEET Physics Electrostatics Questions Part 1

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Question : 57 of 100

Marks: +1, -0

The electric potential at a point (x, y, z) is given by V=x2y−xz3+4
The electric field

→

E

at that point is

(2009)

→
E
=
∧
i
2xy+
∧
j
(X2+y2)+
∧
k
(3xz−y2)
→
E
=
∧
i
z3+
∧
j
xyz+
∧
k
z2
→
E
=
∧
i
(2xy−z3)+
∧
j
xy2+
∧
k
3z2x
→
E
=
∧
i
(2xy+z3)+
∧
j
x2+
∧
k
2xz2

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