Two metal spheres, one of radius {\R} and the other of radius 2 {\R} respectively have the same surface charge density \sigma. They are brought in contact and separated. What will be the new surface charge densities on them? [NEET OD 2019]

Correct Answer is : σ1=53σ,σ2=56σ

\sigma_1=\frac{5}{6} \sigma, \sigma_2=\frac{5}{2} \sigma

\sigma_1=\frac{5}{2} \sigma, \sigma_2=\frac{5}{6} \sigma

\sigma_1=\frac{5}{2} \sigma, \sigma_2=\frac{5}{3} \sigma

\sigma_1=\frac{5}{3} \sigma, \sigma_2=\frac{5}{6} \sigma

Class 12 NEET Physics Electrostatics Questions Part 1

Question : 17 of 100

Marks: +1, -0

Two metal spheres, one of radius R and the other of radius 2R respectively have the same surface charge density σ. They are brought in contact and separated. What will be the new surface charge densities on them?

[NEET OD 2019]

σ1=‌
5
6
σ,‌‌σ2=‌
5
2
σ
σ1=‌
5
2
σ,‌‌σ2=‌
5
6
σ
σ1=‌
5
2
σ,‌‌σ2=‌
5
3
σ
σ1=‌
5
3
σ,‌‌σ2=‌
5
6
σ

Validate

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