The magnetic field of a plane electromagnetic wave is given by \overrightarrow{B}=3 \times 10^{-8} \cos (1.6 \times 10^3 x+48 \times 10^{10} t) \hat{j} then the associated electric field will be: [NEET Re-2022]

Correct Answer is : 9cos(1.6×103x+48×1010t)∧kV∕m

9 \cos (1.6 \times 10^3 x+48 \times 10^{10} t) \hat{k} V \/ m

3 \times 10^{-8} \cos (1.6 \times 10^3 x+48 \times 10^{10} t) \hat{i} {\V} \/ {\m}

3 \times 10^{-8} \sin (1.6 \times 10^3 x+48 \times 10^{10} t) \hat{i} {\V} \/ {\m}

9 \sin (1.6 \times 10^3 x-48 \times 10^{10} t) \hat{k} V \/ m

Class 12 NEET Physics Electromagnetic Waves Questions

Question : 10 of 51

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The magnetic field of a plane electromagnetic wave is given by

→

=3×10−8‌cos(1.6×103x+48×1010t)‌

∧

then the associated electric field will be:

[NEET Re-2022]

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