Class 12 NEET Physics Electromagnetic Induction and Alternating Currents

Initially, the current will pass through the capacitor (and not through the resistance which is parallel to the capacitor). So effective resistance in the circuit is RAB. Therefore the current in the resistor is 2 mA. After some time, the capacitor will become fully charged and will be in its steady state. Now no current will pass through the capacitor and the effective resistance of the circuit will be
(1000+1000)=2000Ω
Therefore current in the resistor
=

V

R

=

2

2000

=1×10−3 A=1 mA