A source S_1 is producing, 10^15 photons per second of wavelength 5000Å.Another source S_2 is producing 1.02\times10^15 photons per second of wave length 5100Å. Then, (power of S_2)/(power of S_1) is equal to (2010)

Class 12 NEET Physics Dual Nature of Matter and Radiation

Question : 50 of 107

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A source S1 is producing, 1015 photons per second of wavelength 5000Å.Another source S2 is producing 1.02×1015 photons per second of wave length 5100Å. Then, (power of S2)/(power of S1) is equal to

(2010)

1.00
1.02
1.04
0.98

Validate

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