Electrons of mass m with de-Broglie wavelength \lambda fall on the target in an X-ray tube. The cutoff wavelength (\lambda_0) of the emitted X-ray is: [NEET 2016 P2]

Correct Answer is : λ0=2mcλ2h

\lambda_0={2m^2c^2\lambda^3}/h^2

Class 12 NEET Physics Dual Nature of Matter and Radiation

Question : 26 of 107

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Electrons of mass m with de-Broglie wavelength λ fall on the target in an X-ray tube. The cutoff wavelength (λ0) of the emitted X-ray is:

[NEET 2016 P2]

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