Class 12 NEET Physics Current Electricity Questions Part 1

To carry a current of 4 ampere, we need four paths, each carrying a current of one ampere. Let r be the resistance of each path. These are connected in parallel. Hence their equivalent resistance will be

r

4

. According tothe given problem

r

4

=5 or r=20Ω
For this purpose two resistances should be connected. There are four such combinations.Hence, the total number of resistance
=4×2=8