Class 12 NEET Physics Current Electricity Questions Part 1

Ratio of cross-sectional areas of thewires =3:1
and resistance of thick wire (R1)=10Ω.
Resistance (R)=ρ

l

A

∝

1

A

Therefore

R1

R2

=

A2

A1

=

1

3

or R2=3R1=3×10=30Ω
and equivalent resistance of these two resistances in series combination
=R1+R2=30+10=40Ω