Class 12 NEET Physics Current Electricity Questions Part 1

Applied voltage (V)=2 V and resistances =3Ω,3Ω,3Ω.
From the given circuit, we find that two resistances are in series and third resistance is in parallel. Therefore equivalent resistance for series resistances =3+3=6Ω. Now it is connected parallel with 3Ω resistance. Therefore

1

R

=

1

3

+

1

6

=

3

6

=

1

2

or R=2Ω
And current flowing in the circuit (I)
=

V

R

=

2

2

=1 A