Class 12 NEET Physics Current Electricity Questions Part 1

According to given parameters inquestion
R=ρ

l

A

⇒100Ω=ρ

3

A

⇒

ρ

A

=

100

3

Thus total resistance of 50 cm wire is
R1=

ρ

A

l=

100

3

×0.5 =

50

3

Ω
The total current in the wire is I=

6

100

A
Therefore potential difference across the two points on the wire separated by a distance of 50 m is
(V)=IR1=

50

3

×

6

100

=1 V