Class 12 NEET Physics Current Electricity Questions Part 1

Current through armCAD,I=

V

8

amp
Potential difference betweenCandA=VC−VA
=

V

8

×4=

V

2

‌volt
Current throughCBD,I′=

V

4

amp
Potential difference between C andB=VC−VB
=

V

4

×1=

V

4

‌volt.
Potential betweenAandB=VA−VB
∴ VA−VB=VC−VB−(VC−VA)=

V

4

−

V

2

=−

V

4

⇒ VA−VB<0 or, VA<VB
As VA<VB, so direction of current will be from B to A