Class 12 NEET Physics Current Electricity Questions Part 1

Let X be the equivalent resistance between S and 6Ω
∴

1

X

=

1

S

+

1

6

.....(i)
Therefore, the equivalent circuit diagram drawn below.For a balanced Wheatstone's bridge, we get

P

Q

=

R

X

or

2

2

=

2

X

⇒ X=2Ω
From eqn. (i), we get

1

2

=

1

S

+

1

6

or ,

1

S

=

2

6

or ,S=3Ω