Class 12 NEET Physics Atoms and Nuclei Questions Part 2

The wavelength of different spectral lines of Lyman series is given by

1

λL

=R[

1

12

−

1

n2

] where m=2,3,4......
where subscript L refers to Lyman.
For longest wavelength, n=2

The wavelength of different spectral series of Balmer series is given by

1

λB

=R[

1

22

−

1

n2

] where n=3,4,5.....
where subscript B refers to Balmer.
For longest wavelength, n=3

Divide (ii) by (i), we get

λLlongest

λBlongest

=

5R

36

×

4

3R

=

5

27