Class 12 NEET Physics Atoms and Nuclei Questions Part 2

Mass number of reactant = 240
BE per nucleon = 7.6 MeV
Mass number of products = 120
BE per nucleon of product = 8.5 MeV
Total gain in BE = (BE) of products – (BE) of reactants.
= [120 + 120] × 8.5 – [240] × 7.6
= (240) × 8.5 – 240 × 7.6
= (2040 – 1824) MeV
Gain in BE = 216 MeV