Following limiting molar conductivities are given as \lambda_{ {\m}( {\H}_2 {\SO}_4)}^0= {\x} {\Scm}^2 {\mol}^{-1} \lambda_{ {\m}( {\K}_2 {\SO}_4)}^0= {\y} {\Scm}^2 {\mol}^{-1} \lambda_{ {\m}( {\CH}_3 {\COOK})}^0= {\z} {\Scm}^2 {\mol}^{-1} \lambda_{ {\m}}^0(. in . {\S} {\cm}^2 {\mol}^{-1}) for {\CH}_3 {\COOH} will be- [NEET OD 2019]

NEET Odisha 2019 Physics and Chemistry

Question : 68 of 90

Marks: +1, -0

Following limiting molar conductivities are given as
λm(H2SO4)0=xScm2mol−1
λm(K2SO4)0=yScm2mol−1
λm(CH3‌COOK)0=zScm2mol−1
λm0(. in .Scm2mol−1) for CH3‌COOH will be-

[NEET OD 2019]

x−y+2z
x+y−z
x−y+z
‌
(x−y)
2
+z

Validate

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