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Question : 88 of 180
Marks:
+1,
-0
Solution:
O2→σ1s2σ*1s2σ2s2σ*2s2σ2Pz2‌‌‌‌π2Py2‌‌‌π*2Py1
             π2Px2‌‌π*2Px1
O2 has a unpaired electrons
N2−→σ1s2σ*1s2σ2s2σ2Pz2‌‌‌‌‌π2Py2‌‌π2Py1
             π2Px2‌‌‌π2Px
N2−has one unpaired electron
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