The major product formed in the following reaction is:-CH_3-C^{|↖{CH}}_{|↙{H}}-CH_2Br\stackrel{CH_3O^{⊖}{––––––––>}}_{CH_3OH}

Correct Answer is : CH3−CH3|C=CH2

CH_3-C^{|↖{CH_3}}_{|↙{H}}-CH_2OCH_3

CH_3-C^{|↖{CH_3}}_{|↙{OCH_3}}=CH_3