NEET Exam Model Paper 3

Amount of 0.1 M AB solution added is =10−5=5mL
0.1M AB left behind in the solution is =0.4mL
0.1M AB used up for coagulation =5−0.4=4.6mL
4.6mL of 0.1M AB contains AB=

(4.6X0.1)

1000

=0.46 milimoles
As total volume of sol after mixing with electrolyte is 10mL, amount of AB required for
Coagulation of 1 L of the sol=46 mill moles, hence flocculation value =46