Steam at 100^\circC is passed into 20 g of water at 10 ^\circC. when water acquires a temperature of 80^\circC, the mass of water present will be: ( Take specific heat of water =1calg^{-1}^\circC^{-1} and latent heat of steam =540calg^{-1})

NEET Exam Model Paper 2

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Steam at 100°C is passed into 20 g of water at 10°C. when water acquires a temperature of 80°C, the mass of water present will be: ( Take specific heat of water =1calg−1°C−1 and latent heat of steam =540calg−1)

24 g
31.5 g
42.5 g
22.5 g

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