NEET Exam Model Paper 2

Given A=B=C
In the first case when

→

A

+

→

B

=

→

C

Δabc is equilateral angle between

→

A

and

→

C

is α=60°
In the second case when

→

A

+

→

B

=

→

C

=0 again Δabc is an equilateral triangle.The vectors

→

A

,

→

B

and

→

C

from a closed triangle,angle between

→

A

and

→

C

is now β=120°
∴β=2α
α=

β

2