NEET Exam Model Paper 10

To move on circular path in a magnetic field, a centripetal force is provide by the magnetic force. When magnetic field is perpendicular to motion of charged particle, then
Centripetal force = magnetic force
That is

mv2

R

=Bqv or R=

mv

Bq

Further, time period of the motion
T=

2πR

v

=

2π( mv Bq )

v

or T=

2πm

Bq

It is independent of both R and v