According to law of photochemical equivalence the energy absorbed (in ergs/mole) is given as (h=6.62 \times 10^{-27} ergs, c=3 \times 10^{10} {cm} {s}^{-1}, N_{A}=6.02 \times 10^{-23} {mol}^{-1}) (Karnataka NEET 2013)

Correct Answer is : 1.196×108λ

\frac{1.196 \times 10^{8}}{\lambda}

\frac{2.859 \times 10^{5}}{\lambda}

\frac{2.859 \times 10^{16}}{\lambda}

\frac{1.196 \times 10^{16}}{\lambda}

Class 11 NEET Chemistry Structure Of Atom Questions

Question : 35 of 84

Marks: +1, -0

According to law of photochemical equivalence the energy absorbed (in ergs/mole) is given as (h=6.62×10−27 ergs,

c=3×1010cms−1,NA=6.02×10−23mol−1)

(Karnataka NEET 2013)

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