In reaction, CH_2=CH_2\stackrel{\Hypochlorous}{──────🢖}_{\acid}M\stackrel{R}{──🢖}|^{CH_2OH}_{↙{CH_2OH}} where, M = Molecule and R = Reagent. M and R are (1997)

Correct Answer is : CH2Cl−CH2OH and aq. NaHCO3.

{CH}_{3} {CH}_{2} {OH} and {HCl}

{CH}_{3} {CH}_{2} {Cl} and {NaOH}

{CH}_{2} {Cl}- {CH}_{2} {OH} and aq. {NaHCO}_{3}.

Class 11 NEET Chemistry Hydrocarbons Questions

Question : 79 of 98

Marks: +1, -0

In reaction,

CH2=CH2

Hypochlorous

──────🢖

acid

──🢖

CH2OH

‌

CH2OH

where, M = Molecule and R = Reagent. M and R are

(1997)

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