In the following reaction H_3C-C^{|↖{CH_3}}_{|↙{CH_3}}-CH=CH_2\stackrel{H_2O{/H^{+}{────────🢖}}} {A}_{{\Major}_{\product}}+B_{\Minor↙{\product}} The major product is (2012)

Correct Answer is : H3C−CH3|C|OH−C|CH3H−CH3

H_3C-C^{|↖{CH_3}}_{|↙{OH}}-C_{|↙{CH_3}}H-CH_3

C_{|↙{OH}}H_2-C^{|↖{CH_3}}_{|↙{CH_3}}-CH_2-CH_3

H_3C-C^{|↖{CH_3}}_{|↙{CH_3}}-CH_{|↙{OH}}-CH_3

H_3C-C^{|↖{CH_3}}_{|↙{CH_3}}-CH_2-C_{|↙{OH}}H_2

Class 11 NEET Chemistry Hydrocarbons Questions

Question : 44 of 98

Marks: +1, -0

In the following reaction

H3C−

CH3

−CH=CH2

H2O/H+

────────🢖

Major

product

Minor

product

The major product is

(2012)

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