The solubility product of AgI at 25^{\circ} {C} is 1.0 \times 10^{-16} {mol}^{2} {L}^{-2} . The solubility of AgI in 10^{-4} {N} solution of {KI} at 25^{\circ} {C} is approximately (in mol {L}^{-1} ) (2003)

Correct Answer is : 1.0×10−12

Class 11 NEET Chemistry Equilibrium Questions Part 1

Question : 64 of 100

Marks: +1, -0

The solubility product of AgI at 25∘C is 1.0×10−16mol2L−2. The solubility of AgI in 10−4N solution of KI at 25∘C is approximately (in mol L−1 )

(2003)

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